5x^2=-6x+8

Solution for 5x^2=-6x+8 equation:

5x^2=-6x+8

We move all terms to the left:

5x^2-(-6x+8)=0

We get rid of parentheses

5x^2+6x-8=0

a = 5; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·5·(-8)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*5}=\frac{-20}{10}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*5}=\frac{8}{10}
=4/5
$